| commit | 17bd5bc0824d86989905d500f0f1d8a35f6ebe90 | [log] [tgz] |
|---|---|---|
| author | Android Build Coastguard Worker <[email protected]> | Thu Jul 15 01:33:02 2021 +0000 |
| committer | Android Build Coastguard Worker <[email protected]> | Thu Jul 15 01:33:02 2021 +0000 |
| tree | 994f7da7a7f4f482fcf3528bbe7ba101c62806b8 | |
| parent | aebf8ebdf7d40de96a0d5865c99d4102bd0c1fdb [diff] | |
| parent | 071e185773740c234ee0a5db98bf0cd07f7abaf1 [diff] |
Snap for 7550844 from 071e185773740c234ee0a5db98bf0cd07f7abaf1 to mainline-os-statsd-release Change-Id: Iaae25c456fc6d20cc1ade19a7c6969b214403cb5
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?