| commit | a108c0a5c0b0e5ff9922b2b22af062c13cd0e094 | [log] [tgz] |
|---|---|---|
| author | Android Build Coastguard Worker <[email protected]> | Tue May 10 07:01:43 2022 +0000 |
| committer | Android Build Coastguard Worker <[email protected]> | Tue May 10 07:01:43 2022 +0000 |
| tree | 994f7da7a7f4f482fcf3528bbe7ba101c62806b8 | |
| parent | bce726b9d3f026df9c5a05a4791db7e150974f97 [diff] | |
| parent | 8640dcfecb8596d172114e2ecba01f4887346c13 [diff] |
Snap for 8564071 from 8640dcfecb8596d172114e2ecba01f4887346c13 to mainline-tethering-release Change-Id: I533b525ac1a12a8b370e420b2f8072b78b512443
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?