| commit | 5b86fa39a618f7b4a0e4eae66dd2b3c908ef3497 | [log] [tgz] |
|---|---|---|
| author | Android Build Coastguard Worker <[email protected]> | Wed Nov 02 03:12:41 2022 +0000 |
| committer | Android Build Coastguard Worker <[email protected]> | Wed Nov 02 03:12:41 2022 +0000 |
| tree | 1658cb90958498bab43d7ddd0aa2ef61be41ff5d | |
| parent | 7c8f9ce48333b73d8d793bee3b24a581b3fb4e6c [diff] | |
| parent | 131042402ea3d5403761b71e3bf127ad1d842039 [diff] |
Snap for 9245572 from 131042402ea3d5403761b71e3bf127ad1d842039 to udc-d1-release Change-Id: Ic4893b780c2e7fb0136babbd94325af6fa2ef4ad
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?